1. 涓涓撴暟瀛...
1銆佽繃镣笰(1,2),B(-1,-5)镄勭洿绾挎柟绋嬭句负y=kx+b锛屽皢涓ょ偣浠ｅ叆寰
k+b=2锛-k+b=-5瑙ｆ柟绋嫔缑k=7/2,b=-3/2锛屽洜姝ゆ墍姹傜洿绾挎枩鐜囦负7/2锛
鐩寸嚎鏂圭▼涓簓-2=7/2(x-3)锛岃嚜宸辨暣鐞嗐
2銆丩1鏂灭巼涓(4-m)/(m+2)=L2镄勬枩鐜-2锛屽嵆(4-m)/(m+2)=-2锛岃В涔嫔缑m=-8
3銆侊纸1锛夊瀭鐩翠簬x+3=0镄勭洿绾挎枩鐜囦负0锛岃繃锛3锛岋紞2锛夋枩鐜囦负0镄勭洿绾夸负y=-2
锛2锛夊瀭鐩翠簬y-2=0镄勭洿绾垮钩琛屼簬y杞存媶绛旓纴锲犳よ繃锛3锛岋紞2锛夊钩琛屼簬y杞寸殑鐩寸嚎涓簒=3銆
锛3锛夋枩鐜囦负1/2锛屽垯镓姹傜洿绾挎柟绋嬩负y+2=1/2(x-3)锛岃嚜宸辨暣鐞嗐
4銆乴镄勬枩鐜囦负(-1-1)/(-5-2)=2/7锛屾墍姹傜洿绾挎柟绋嬩负镞呴珮鎱y-3=2/7(x-2)锛岃嚜宸辨暣鐞嗐
5銆佺洿绾緼B镄勬枩鐜囦负(-5-3)/(-1-5)=4/3锛屽瀭鐩村钩鍒嗙嚎镄勬枩蹇靛甫鐜囦负锛3/4锛岀嚎娈础B镄勪腑镣逛负((5-1)/2,(3-5)/2)=(2,-1),镓姹傚瀭鐩村钩鍒嗙嚎涓 y+1=-3/4(x-2)
6銆丩1鏂灭巼涓(0-4)/(3-2)=-4锛孡1鏂圭▼涓簓=-4(x-3)
鐢盠1涓嶭2鍨傜洿锛屽垯L2鏂灭巼涓1/4锛屽垯L2鏂圭▼涓簓-4=1/4(x-2)锛岃嚜宸辨暣鐞嗐