1. 涓涓撴暟瀛...
1銆佽繃鐐笰(1,2),B(-1,-5)鐨勭洿綰挎柟紼嬭句負y=kx+b錛屽皢涓ょ偣浠ｅ叆寰
k+b=2錛-k+b=-5瑙ｆ柟紼嬪緱k=7/2,b=-3/2錛屽洜姝ゆ墍奼傜洿綰挎枩鐜囦負7/2錛
鐩寸嚎鏂圭▼涓簓-2=7/2(x-3)錛岃嚜宸辨暣鐞嗐
2銆丩1鏂滅巼涓(4-m)/(m+2)=L2鐨勬枩鐜-2錛屽嵆(4-m)/(m+2)=-2錛岃В涔嬪緱m=-8
3銆侊紙1錛夊瀭鐩翠簬x+3=0鐨勭洿綰挎枩鐜囦負0錛岃繃錛3錛岋紞2錛夋枩鐜囦負0鐨勭洿綰誇負y=-2
錛2錛夊瀭鐩翠簬y-2=0鐨勭洿綰垮鉤琛屼簬y杞存媶絳旓紝鍥犳よ繃錛3錛岋紞2錛夊鉤琛屼簬y杞寸殑鐩寸嚎涓簒=3銆
錛3錛夋枩鐜囦負1/2錛屽垯鎵奼傜洿綰挎柟紼嬩負y+2=1/2(x-3)錛岃嚜宸辨暣鐞嗐
4銆乴鐨勬枩鐜囦負(-1-1)/(-5-2)=2/7錛屾墍奼傜洿綰挎柟紼嬩負鏃呴珮鎱y-3=2/7(x-2)錛岃嚜宸辨暣鐞嗐
5銆佺洿綰緼B鐨勬枩鐜囦負(-5-3)/(-1-5)=4/3錛屽瀭鐩村鉤鍒嗙嚎鐨勬枩蹇靛甫鐜囦負錛3/4錛岀嚎孌礎B鐨勪腑鐐逛負((5-1)/2,(3-5)/2)=(2,-1),鎵奼傚瀭鐩村鉤鍒嗙嚎涓 y+1=-3/4(x-2)
6銆丩1鏂滅巼涓(0-4)/(3-2)=-4錛孡1鏂圭▼涓簓=-4(x-3)
鐢盠1涓嶭2鍨傜洿錛屽垯L2鏂滅巼涓1/4錛屽垯L2鏂圭▼涓簓-4=1/4(x-2)錛岃嚜宸辨暣鐞嗐